题目
微分方程 x'' = (1)/(sqrt(y))的通解为 () A. x = C_(2)pm [ (2)/(3)(sqrt(y) + C_(1))^(3)/(2) - 2C_(1)sqrt(sqrt(y) + C_{1)}], (C_(1), C_(2) 相互独立) B. x = C_(2)pm [ (3)/(2)(sqrt(y) + C_(1))^(2)/(3) - 2C_(1)sqrt(sqrt(y) + C_{1)}], (C_(1), C_(2) 相互独立) C. x = C_(2)pm [ (2)/(3)(sqrt(y) + C_(1))^(3)/(2) + C_(1)sqrt(sqrt(y) + C_{1)}], (C_(1), C_(2) 相互独立) D. x = C_(2)pm [ 2(sqrt(y) + C_(1))^(3)/(2) - (2)/(3) C_(1)sqrt(sqrt(y) + C_{1)}], (C_(1), C_(2) 相互独立)
$$ 微分方程 $x'' = \frac{1}{\sqrt{y}}$的通解为 () $$
- A. $$ $x = C_{2}\pm \left[ \frac{2}{3}\left(\sqrt{y}\ \ + C_{1}\right)^{\frac{3}{2}}\ \ - 2C_{1}\sqrt{\sqrt{y}\ \ + C_{1}}\right]$, $(C_{1}, C_{2}\ \ 相互独立)$ $$
- B. $$ $x = C_{2}\pm \left[ \frac{3}{2}\left(\sqrt{y}\ \ + C_{1}\right)^{\frac{2}{3}}\ \ - 2C_{1}\sqrt{\sqrt{y}\ \ + C_{1}}\right]$, $(C_{1}, C_{2}\ \ 相互独立)$ $$
- C. $$ $x = C_{2}\pm \left[ \frac{2}{3}\left(\sqrt{y}\ \ + C_{1}\right)^{\frac{3}{2}}\ \ + C_{1}\sqrt{\sqrt{y}\ \ + C_{1}}\right]$, $(C_{1}, C_{2}\ \ 相互独立)$ $$
- D. $$ $x = C_{2}\pm \left[ 2\left(\sqrt{y}\ \ + C_{1}\right)^{\frac{3}{2}}\ \ - \frac{2}{3}\ \ C_{1}\sqrt{\sqrt{y}\ \ + C_{1}}\right]$, $(C_{1}, C_{2}\ \ 相互独立)$ $$
题目解答
答案
A