题目
1.将下列函数转换为分段函数形式.-|||-(1) =|x|+1;-|||-(2) =|x-2|;
题目解答
答案
0)\\
&-x\ \ (x\le 0)
\end{aligned}
\right.
\\&=\left \{
\begin{aligned}
&x +1\ \ (x>0)\\
&-x+1\ \ (x\le 0) \\
\end{aligned}
\right.\\
&(2)y=|x-2|=\left \{
\begin{aligned}
&x-2 \ \ (x>2)\\
&-(x-2)\ \ (x\le 2)
\end{aligned}
\right.
\\&=
\left \{
\begin{aligned}
&x-2 \ \ (x>2)\\
&-x+2\ \ (x\le 2)
\end{aligned}
\right.
\end{aligned}" data-width="335" data-height="215" data-size="18877" data-format="png" style="max-width:100%">