设工厂A和工厂B的产品次品率分别为1%和-|||-2%, 现从一批由A和B的产品分别占60%和40%-|||-的产品中随机抽取一件,若用A,B分别表示-|||-甲、乙两厂的产品,C表示产品为次品,则-|||-P(B|C)= __

甲袋中装有9个兵乓球,其中3个白球,6个黄-|||-球,乙袋中也装有9个兵乓球,5个白球,4个-|||-黄球。首先从甲袋中任选一球放入乙袋,再从-|||-乙袋中任取一球放入甲袋,则甲袋中白球数目-|||-不会发生变化的概率为[填空1](分数形式).

1357.已知 tan x=1, in (dfrac (pi )(2),dfrac (3pi )(2)), 则 =-|||-A. dfrac (pi )(4) B. dfrac (3pi )(4) C.dfrac (5pi )(4) D. dfrac (7pi )(4)

3.设A,B,C为随机事件, (ABC)=0, 且 lt P(C)lt 1, 则一定有 () .-|||-(A) P(ABC)=P(A)P(B)P(C)-|||-(3) (A+B)|C'=P(A|C)+P(B|C)-|||-(C) P(A+B+C)=P(A)+P(B)+P(C)-|||-(D) P((A+B)|C)=P(A|C)+P(B|C)

(3)lim_(xto0)(xsin(1)/(x)+(sin2x)/(x))=____

[题目]-|||-曲线 (x)=dfrac ({x)^2+x}({x)^2-1} 渐近线的条数为 ()-|||-(A)0 (B)1 (C)2 (D)3

1.已知 为两个随机事件,且 (A)=dfrac (1)(2) , (B)=dfrac (3)(5) , (B|A)=dfrac (4)(5), 求:-|||-(1) (Acup B); (2) (A-B); (3) [ overline (B)|(Acup B)]

不等式 3x + 2 > 2 的解集为（ ）A．(0，2) B．(0，3) C．(0,+infty ) D．(0,+infty )

5.单选题极限lim _(xarrow dfrac {pi )(2)}((1+cot x))^tan x=( )A.1B.eC.lim _(xarrow dfrac {pi )(2)}((1+cot x))^tan xD.不存在

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